High School Question about Planck's Function

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Integrating Planck's function for blackbody radiation results in an area under the curve that is smaller than the spectral radiance at individual wavelengths due to differences in units. Radiance is measured in watts per steradian per square meter, while spectral radiance is measured in watts per steradian per square meter per hertz. The normalization of the spectral radiance curve, often set to a maximum value of 1 at the peak, can also contribute to this discrepancy. Understanding these unit differences is crucial for accurate comparisons. This highlights the importance of unit consistency in analyzing blackbody radiation.
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Hi! I have a question about integrating Planck's function of blackbody radiation. Why is it that the area under the blackbody curve will be less than the spectral radiance of individual wavelengths? For example, integrating the Sun's curve over all wavelengths yields a smaller value than the spectral radiance of just its peak wavelength.
 
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Radiance and spectral radiance have different units. The SI unit of radiance is the watt per steradian per square metre (W·sr−1·m−2), while that of spectral radiance in frequency is the watt per steradian per square metre per hertz (W·sr−1·m−2·Hz−1)

Often the spectral radiance curve for the sun is normalized to have a max value of 1 at the peak (and is called the luminosity function I think). So probably it a normalization issue...check the units.
 
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