Question about potential difference?

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SUMMARY

The discussion revolves around calculating the linear charge density (λ) of a long wire using the potential difference measured by a voltmeter. The voltmeter reads 575 V when one probe is placed 2.5 cm from the wire and the other 3.5 cm away. The relevant equation used is Va-Vb = λ/(2πε0) * ln(rb/ra). The confusion arises regarding the interpretation of the voltmeter reading, specifically whether it represents Va-Vb or Vb-Va, leading to the conclusion that only the absolute value of λ can be determined from the given data.

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  • Understanding of electrostatics and electric potential
  • Familiarity with the concept of linear charge density (λ)
  • Knowledge of logarithmic functions and their application in physics
  • Basic proficiency in using voltmeters for measuring potential difference
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  • Study the derivation of the electric potential due to a line charge
  • Learn about the properties of logarithms in physics calculations
  • Explore the concept of electric field and its relation to potential difference
  • Investigate common mistakes in interpreting voltmeter readings
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Students studying electrostatics, physics educators, and anyone involved in solving problems related to electric potential and charge distributions.

ehabmozart
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Question about potential difference??

Homework Statement



A very long wire carries a uniform linear charge density λ
Using a voltmeter to measure potential difference, you find that
when one probe of the meter is placed 2.5 cm from the wire and
the other probe is 1cm farther from the wire, the meter reads 575 V
(a) What is λ?

Homework Equations



Va-Vb= λ/2∏ε0 * ln(rb/ra)


The Attempt at a Solution



My first question is what does the voltmeter read? Va-Vb or Vb-Va? ... In this case I assume it is Vb-Va.. So in our attempt it should be -575= λ/2∏ε0 * ln(3.5/2.5) .. But this doesn't yield to the answer... Any thoughts!?
 
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ehabmozart said:
My first question is what does the voltmeter read? Va-Vb or Vb-Va? ... In this case I assume it is Vb-Va.. So in our attempt it should be -575= λ/2∏ε0 * ln(3.5/2.5) .. But this doesn't yield to the answer... Any thoughts!?

The question only says that |Vb-Va| is 575 V. So you can only find|λ|.
 

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