What is the Potential Difference in a Non-Uniform Electric Field?

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Homework Help Overview

The problem involves calculating the potential difference in a non-uniform electric field defined by the equation Ex = (4.00 N/C·m) x, with specific points A and B located on the y and x axes, respectively. Participants are exploring the implications of the electric field's non-uniformity on the potential difference calculation.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the integral form of the potential difference and question the appropriateness of using a simplified approach for non-uniform fields. There is confusion regarding the distance used in the integral and the significance of the chosen path for integration.

Discussion Status

The discussion is ongoing, with participants raising questions about the correct approach to integration in a non-uniform electric field. Some guidance has been offered regarding the limitations of using certain equations for uniform fields, but no consensus has been reached on the best method to proceed.

Contextual Notes

Participants note the specific coordinates of points A and B and the implications of their locations on different axes, which may affect the integration path. There is also mention of the potential significance of the chosen datum for the y-coordinate.

PhysicsInNJ
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Homework Statement


The electric field in a region of space has the components Ey = Ez = 0 and Ex = (4.00 N/C·m) x. Point A is on the y axis at y = 3.60 m, and Point B is on thex axis at x = 3.00 m. What is the potential difference VBVA?

Homework Equations


Vb- Vi = -∫ba E * dS

The Attempt at a Solution


The integral should become E*d, or 4*0.6 , but that is incorrect
The correct answer is -18V
 
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PhysicsInNJ said:

The Attempt at a Solution


The integral should become E*d, or 4*0.6 , but that is incorrect
The correct answer is -18V
Where does the 0.6 come from? Note that the two points are on different axes.
 
What's a good choice of path integration? Does the datum y = 3.6, as opposed to some other y number, have any significance?
 
PhysicsInNJ said:
The integral should become E*d
In addition to what the others said, ##\Delta V = Ed## only holds for uniform fields. You don't have a uniform field in this problem.
 

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