Question about the direction of a vector

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SUMMARY

The discussion focuses on calculating the direction of vector C, defined as C = A - B, where A = 3i - 6j and B = 4i - 5j. The correct calculation yields C = -1i - 1j, leading to an angle of 225 degrees when applying the arctangent function. The initial attempt incorrectly stated the angle as 45 degrees due to miscalculations in the tangent function. Proper notation and clarity in mathematical expressions are emphasized for accurate problem-solving.

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Homework Statement


Let A= 3i - 6j and B= 4i - 5j. The direction of the vector C = A - B is at an angle of?

Homework Equations


Magnitude= ( a^2 + b^2 ) ^1/2
Tan^-1 = b/a

The Attempt at a Solution


A-B =
3-4 i -6--5j
-1i -1j
Tan^-1 = -1/-1 = 45
45+180 = 225

Is this correct?
 
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Sall1230 said:
A-B =
3-4 i -6--5j
-1i -1j
Tan^-1 = -1/-1 = 45
45+180 = 225

Is this correct?
You really need to work on your notation here, the first line is missing parentheses or basis vectors for two terms, there is no equality sign between the second line and the third line, the inverse tangent function has no argument and -1/-1 is 1 and not 45.

That being said, what you are actually doing (which is not what you are writing) is correct.
 
As this is a 2D problem it's not hard to draw it.
 

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