Question about the energy of 2 blocks with a spring between them

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SUMMARY

The discussion revolves around the conservation of kinetic energy in a system of two blocks separated by a spring. Participants debate the implications of elastic collisions and the conditions under which kinetic energy remains constant. The correct understanding emphasizes that if the blocks are stationary before release, their kinetic energy cannot be conserved in motion post-release. The conversation highlights the necessity of grasping fundamental physics concepts, particularly the expression for kinetic energy, which is defined as 1/2 mv².

PREREQUISITES
  • Understanding of kinetic energy and its formula (1/2 mv²)
  • Basic principles of elastic collisions in physics
  • Concept of conservation laws in mechanics
  • Ability to derive and manipulate physics equations
NEXT STEPS
  • Study the principles of elastic and inelastic collisions in detail
  • Learn about conservation of momentum and energy in closed systems
  • Practice solving problems involving kinetic energy and potential energy transformations
  • Explore advanced physics resources or textbooks for deeper theoretical understanding
USEFUL FOR

Students preparing for physics examinations, particularly those studying mechanics at the AS level, and anyone seeking to strengthen their understanding of kinetic energy and conservation principles in physics.

hello478
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Homework Statement
image below
Relevant Equations
energy equations
1711745954025.png

My attempt:
my answer was b
correct answer is d
 
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Can you explain why you picked b ?
Do you know the expression for kinetic energy?
 
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BvU said:
Can you explain why you picked b ?
Do you know the expression for kinetic energy?
because before the release they are stationary
and it is elastic collision, maybe...
so the kinetic energies would add upto 0
so that the total KE is conserved...
 
hello478 said:
so that the total KE is conserved...
"Conserved" means "it is the same" throughout whatever is going on. Before release the sum of kinetic energies is zero because neither block is moving. If, as you claim, this sum is conserved, then neither block should be moving after release. Do you think that is the case?
 
hello478 said:
because before the release they are stationary
and it is elastic collision, maybe...
so the kinetic energies would add upto 0
so that the total KE is conserved...
Why would kinetic energy be conserved? This would mean the blocks just remain stationary as kinetic energy is non-negative.
 
BvU said:
Do you know the expression for kinetic energy?
 
1/2 mv2
 
oh ok so, the velocities direction would not be considered.... thats the only thing i understand uptill now
 
hello478 said:
oh ok so, the velocities direction would not be considered.... thats the only thing i understand uptill now
It sounds to me that based upon your many posts with seemingly little thought behind your attempts that what you really need to do before attempting these problems is to sit down with your book and try to understand the theory behind the problems first. Otherwise you will just be shooting wildly with your answers.
 
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  • #10
Orodruin said:
It sounds to me that based upon your many posts with seemingly little thought behind your attempts that what you really need to do before attempting these problems is to sit down with your book and try to understand the theory behind the problems first. Otherwise you will just be shooting wildly with your answers.
ill try to do that, though i sort of know what the book says... physics is just not my thing so its difficult for me to grasp
when i read the book, everything is so easy until the questions blow my mind...
 
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  • #11
Sort of know typically won’t do. You need to actually know and most of all understand what it says. Work through any derivations so that you understand where things come from, do the same with any examples. Go equation by equation and make sure you understamd how and why it came about.
 
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  • #12
hello478 said:
ill try to do that, though i sort of know what the book says... physics is just not my thing so its difficult for me to grasp
when i read the book, everything is so easy until the questions blow my mind...
Tip (that worked for me): while reading, invent tough exercises you could test your classmates with.

Re 'not my thing': seems to me math isn't either. But systematic reasoning and logical thinking are indispensable in all fields! (what's yours?)

##\ ##
 
  • #13
BvU said:
Tip (that worked for me): while reading, invent tough exercises you could test your classmates with.
ok ill try to do that too, but i dont have much time till my exams...
and im a private student
so... i dont have classmates 😅
BvU said:
(what's yours?)
and im currently doing physics AS levels and biology A levels
 
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