Question about the General form to normal form of Diff Eq

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SUMMARY

The differential equation \(x(y')^2 - 4y' - 12x^3 = 0\) cannot be expressed in the normal form \(dy/dx = f(x,y)\) due to the presence of two roots when isolating \(y'\). The quadratic nature of the equation indicates that \(y'\) cannot be uniquely determined as a function of \(x\) and \(y\). Therefore, the conclusion is that the equation does not meet the criteria for normal form.

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  • Familiarity with quadratic equations and their solutions
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Saladsamurai
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Homework Statement


The diff eq x(y&#039;)^2-4y&#039;-12x^3=0[/tex] takes the general form. Determine if the equation can be put in the normal form dy/dx=f(x,y)<br /> <br /> Well I have tried algebraically to isolate y&#039; and find that I cannot. So my question is, I have decided the answer is no. Now how do I explain why y&#039; cannot be isolated? Maybe this question is stupid...
 
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Isolating y' is just solving a quadratic equation. But they have two roots. Does that mean it's not a normal form? That's for you to answer. I don't know.
 

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