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- Homework Statement
- A capacitor of capacitance 7.2pF consists of two parallel metal plates separated by an

insulator of thickness 1.2mm. The area of overlap between the plates is 4.0 × 10−4m2.

Calculate the permittivity of the insulator between the capacitor plates.

- Relevant Equations
- capacitance = Eo Er A /d

the answer is 2.16*10^-11

what i don' t understand about the question is why did they not use the constant Eo 8.85418782 × 10-12

in this case as there is a insulator occupying the area inbetween does that mean then their is no free space ??

Also in this equation the variable A is the area of each capacitor plate or both together ?

They mentioned "area of overall" but I am not sure what they mean by this.

thank you if you reply.

what i don' t understand about the question is why did they not use the constant Eo 8.85418782 × 10-12

in this case as there is a insulator occupying the area inbetween does that mean then their is no free space ??

Also in this equation the variable A is the area of each capacitor plate or both together ?

They mentioned "area of overall" but I am not sure what they mean by this.

thank you if you reply.