Question about the Triple Product

  • Thread starter Thread starter influx
  • Start date Start date
  • Tags Tags
    Product
Click For Summary
SUMMARY

The discussion centers on the properties of the triple product in vector calculus, specifically addressing the equation a⋅(b x a) = 0. Participants confirm that the dot product is bi-linear and symmetric, allowing for the interchange of terms in the expression. Additionally, the identity involving the cross product is utilized to demonstrate that the third term equals zero, reinforcing the anti-symmetry of the cross product where a x a = 0.

PREREQUISITES
  • Understanding of vector calculus concepts
  • Familiarity with the properties of dot and cross products
  • Knowledge of linear algebra, specifically bi-linearity and symmetry
  • Ability to manipulate vector identities and equations
NEXT STEPS
  • Study the properties of the cross product in depth
  • Learn about vector identities and their applications in physics
  • Explore examples of the triple product in real-world scenarios
  • Investigate advanced topics in vector calculus, such as differential forms
USEFUL FOR

Students of physics and mathematics, educators teaching vector calculus, and professionals applying vector analysis in engineering and computer graphics.

influx
Messages
162
Reaction score
1

Homework Statement



upload_2017-5-30_15-44-59.png
[/B]

Homework Equations


a⋅(b x a) = 0

The Attempt at a Solution



Is my working below correct? In particular, can you apply the rCB to both the first part of the bracket (0.2j) and the second part (w x rCB) individually like that?

upload_2017-5-30_15-45-17.png
My second question relates to:

upload_2017-5-30_15-45-30.png


Is that correct? Does it matter if rCB is multiplied at the end or start? I am inclined to think it doesn't as it's a dot product?
 
Physics news on Phys.org
Both are correct. The first because the dot product is (bi-)linear, the second, because it is symmetric.
For the third term to equal zero, you can use the identity ##(\vec{a}\times \vec{b}) \cdot \vec{c} = (\vec{b}\times \vec{c}) \cdot \vec{a} = (\vec{c}\times \vec{a}) \cdot \vec{b}## and the anti-symmetry of the cross product: ##\vec{a}\times \vec{a} = \vec{0}##.
 

Similar threads

Replies
2
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 44 ·
2
Replies
44
Views
15K
  • · Replies 1 ·
Replies
1
Views
1K