Question about using derivatives

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Cbray
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Homework Statement


Find the approximate percentage changes in the given function y = f(x) that will result from an increase of 2%
y = x2

Homework Equations





The Attempt at a Solution


dy/dt = dx/dt * d/dx * x2
dy/dt = dx/dt * 2x
dy/dt = 2/100 * 2x
dy/dt = 4x% ? I don't know if I did this right but apparently in the back of the book I'm not suppose to have the x in there, why not?
 
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Would it be because your supposed to take the second derivative of it? That would make it just 2. I think as the question wants no variables in it too.
 
hvidales said:
Would it be because your supposed to take the second derivative of it? That would make it just 2. I think as the question wants no variables in it too.

I don't think that is correct...
 
What is 't'? You have [itex]y = x^2[/itex] and x seems to have no dependence on a parameter 't'. You simply need to determine [itex]{{dy}\over{dx}}[/itex]

And no, there are no second derivatives involved.
 
Pengwuino said:
What is 't'? You have [itex]y = x^2[/itex] and x seems to have no dependence on a parameter 't'. You simply need to determine [itex]{{dy}\over{dx}}[/itex]

And no, there are no second derivatives involved.

Do you mind filling me in a bit more, i.e. is my working wrong apart from that
 
Last edited:
[solved]
dy/dx=2x
dy/y=2x dx/x2
dy/y=2 * 2/100
dy/y = 4%