- #1
Casimi
- 11
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Homework Statement
An athlete executing a long jump leaves the ground at a 31.6° angle and travels 7.78 m. What was the take-off speed?
I have tried to solve this question but somehow keep arriving at the wrong answer. The formula that I derived is :
distance=V(initial)*sin^2(theta)/g
Where am I going wrong here? Any help would be appreciated.