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Question Concerning The Coefficient of Friction: Block on a Rough Inclined Plane
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[QUOTE="UnknownGuy, post: 5999677, member: 613082"] I will write down the calculations in the pictures here just for clarification. First picture: For P(min), the box will be on the point of sliding down with P pushing up the slope. (1):20gcos(60)μ+P(min)=20gsin(60) For P(max), the box will be on the point of going up with P pushing up the slope. (2):P(max)=20gcos(60)μ+20gsin(60) Setting P(max)=2P(min) and solving (1) and (2) gives μ=0.577 Second picture: For P(min), the box will be on the point of sliding downwards with P pushing down the slope (1):P+20gsin(60)=20gcos(60)μ For P(max), the box will be on the point of sliding up with P pushing up the slope (2):P=20gcos(60)μ+20gsin(60) Setting P(max)=2P(min) and solving (1) and (2) gives μ=5.20 Note: I looked it up and found that the largest coefficients of friction never surpass 1.5(ex: dry aluminum on self has μ=1.35) let alone alone 5! Is this enough proof to regard the second method as incorrect? [/QUOTE]
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Question Concerning The Coefficient of Friction: Block on a Rough Inclined Plane
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