Sombrero Messages 14 Reaction score 0 Thread starter Jul 20, 2007 #1 Sorry for bothering... How does righthand side of formula 5.94 is derived from its left handside after some approximation? Probably it is very simple question but I could't get that expression Thank u very much Attachments page.pdf page.pdf 227.5 KB · Views: 392
Sorry for bothering... How does righthand side of formula 5.94 is derived from its left handside after some approximation? Probably it is very simple question but I could't get that expression Thank u very much
George Jones Staff Emeritus Science Advisor Gold Member Messages 7,643 Reaction score 1,602 Jul 20, 2007 #2 Using [itex]e^2 = 16 \pi^2 \alpha^2,[/itex] the left side is [tex]\frac{2 \pi \alpha^2}{4E^2 + 4E \omega cos \theta}.[/tex] Now use an exact expression for [itex]E^2[/itex] and a two-term approximation to [itex]E[/itex] to get the right side. Last edited: Jul 20, 2007
Using [itex]e^2 = 16 \pi^2 \alpha^2,[/itex] the left side is [tex]\frac{2 \pi \alpha^2}{4E^2 + 4E \omega cos \theta}.[/tex] Now use an exact expression for [itex]E^2[/itex] and a two-term approximation to [itex]E[/itex] to get the right side.