Question: How can I solve these Number Theory/Expansion homework problems?

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Homework Statement


a)True or False :
[tex]\underbrace{111111111...1}[/tex] is a prime number .
[tex]91 times[/tex]

b) Find n such that -:
[tex]2\times 2^2+ 3\times2^3+4\times2^4+ \cdots + n\times2^n=2^{n+10}[/tex]




Homework Equations




The Attempt at a Solution



I have no idea about a). The number is not divisible by 3,7,11...but i can't go on dividing all the way like this. How do i resolve this into prime factors(if possible) ? Do i use binomial theorem and how ?

About b), LHS is an AGP . I tried taking the [tex]\ n\times2^n[/tex] to RHS and then dividing by 2^2...but that doesn't seem to help ?
 
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NateTG said:
Here are some hints...
1.
a) 91 is composite

Umm i don't understand...how does 91 being composite influence divisibility ?
Could you please explain in abit more detail
Thx
 
f(x) said:
Umm i don't understand...how does 91 being composite influence divisibility ?
Could you please explain in abit more detail
Thx

one reason that it helps is because 91=7x13 means that you can chop the number into segments like
[tex]\underbrace{\underbrace{1111111}_{7\; times}\underbrace{1111111}_{7\; times}\ldots\underbrace{1111111}_{7\; times}}_{13\; times}[/tex]

and if 1111111 is not a prime then you are done. Otherwise more work needed.
 
[tex]11 + 1100 + 11 0000 + 11 000000 ...[/tex]

O god damn it, 91's an odd number nvm me didn't notice
 
Last edited:
For problem (b) you might want to consider the sum to n terms of
[tex]1+2x+3x^2+4x^3+...+nx^{n-1}[/tex]
 
If i am not mistaken (b)'s answer is [tex]2^9+1[/tex]
but you need to do the workings yourself..
 
NateTG said:
111,111,111,111,111=111*1,001,001,001,001

How did you get that ?


truewt said:
If i am not mistaken (b)'s answer is 2^9+1

Yeah 513 was surely an option...
 
mjsd said:
one reason that it helps is because 91=7x13 means that you can chop the number into segments like
[tex]\underbrace{\underbrace{1111111}_{7\; times}\underbrace{1111111}_{7\; times}\ldots\underbrace{1111111}_{7\; times}}_{13\; times}[/tex]

and if 1111111 is not a prime then you are done. Otherwise more work needed.

1111111 = 239 x 4649