Question on both Time Dilation and Lorentz Contraction

In summary, the conversation discusses the concepts of time dilation and Lorentz contraction in reference to two events observed from different reference frames, and the resulting discrepancy in time and length measurements between the two frames. The discussion also addresses the confusion around the "twin paradox" and how it can be resolved.
  • #1
2
0
Hi guys,

There's a couple questions that I've been trying to figure out that I have not been able to make much progress on.

1. Time Dilation

the equation states that T' = Lorentz Factor * T0
So the Lorentz factor will always be > 1 because v < c

So then, if, let's say, there's 2 events, A and B. There are 2 reference frames, a guy on Earth and a guy moving in a spaceship at a very high speed.

Event A: a stopwatch on Earth displays t = 0 s
Event B: a stopwatch on Earth displays t = 30 s

So, on earth, T0 = 30
Let's assume the lorentz factor = 2

Doesn't this mean, then, according to the equation, that the guy on the spaceship measures 60 seconds between events A and B? Doesn't this mean that in the duration of 30 seconds passing on earth, 60 seconds has passed for the guy in the spaceship, meaning that the guy on the spaceship is aging faster than the guy on earth, completely counter to the established theory?


2. Lorentz Contraction Derivation

I understand that to derive the Lorentz contraction, you use

l0 = x2-x1 reference frame of earth
l = x2' - x1' reference frame of spaceship

so then, since x1 = L (x1' + vt')
x2 = L (x2' + vt')

you can write x2-x1 = L (x2'-x1')
So, l = l0/L, the Lorentz contraction formula.

My question is, why couldn't you have also used the reverse set of equations

x1' = L (x1-vt)
x2' = L (x2-vt)

to get x1'-x2' = L (x1-x2)
and then, in this case, l = l0 * L, which is the exact opposite result?


I think I'm probably thinking about this the wrong way, so if someone could give me some help that would be really appreciated.
 
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  • #2
1] you plugged in for the wrong T's; the guy on the spaceship experiences 15 seconds.

2] you can use (1) to derive 2. If the guy on the spaceship experiences half the time, and they both agree on his velocity (relative to light as they must), then the distance must be half as along.
 
  • #3
Tyrusaur said:
1. Time Dilation

the equation states that T' = Lorentz Factor * T0
So the Lorentz factor will always be > 1 because v < c

So then, if, let's say, there's 2 events, A and B. There are 2 reference frames, a guy on Earth and a guy moving in a spaceship at a very high speed.

Event A: a stopwatch on Earth displays t = 0 s
Event B: a stopwatch on Earth displays t = 30 s

So, on earth, T0 = 30
Let's assume the lorentz factor = 2

Doesn't this mean, then, according to the equation, that the guy on the spaceship measures 60 seconds between events A and B?
That's right.
Doesn't this mean that in the duration of 30 seconds passing on earth, 60 seconds has passed for the guy in the spaceship, meaning that the guy on the spaceship is aging faster than the guy on earth, completely counter to the established theory?
Realize that the effect is completely symmetric: Earth observers will measure 60 Earth seconds for a spaceship clock to measure 30 seconds.

Don't confuse this with the "twin paradox", where the symmetry is broken.


2. Lorentz Contraction Derivation

I understand that to derive the Lorentz contraction, you use

l0 = x2-x1 reference frame of earth
l = x2' - x1' reference frame of spaceship

so then, since x1 = L (x1' + vt')
x2 = L (x2' + vt')

you can write x2-x1 = L (x2'-x1')
So, l = l0/L, the Lorentz contraction formula.

My question is, why couldn't you have also used the reverse set of equations

x1' = L (x1-vt)
x2' = L (x2-vt)

to get x1'-x2' = L (x1-x2)
and then, in this case, l = l0 * L, which is the exact opposite result?
Again, length contraction is completely symmetric. In the first case, your "stick" is in the Earth frame and is being measured by the spaceship observers (who measure the position of the ends at the same time)--the stick is measured to have contracted.

In the second case you have the stick in the spaceship frame, so it is Earth observers who see it contracted.
 
  • #4
Tyrusaur said:
Hi guys,

There's a couple questions that I've been trying to figure out that I have not been able to make much progress on.

1. Time Dilation

the equation states that T' = Lorentz Factor * T0
So the Lorentz factor will always be > 1 because v < c

So then, if, let's say, there's 2 events, A and B. There are 2 reference frames, a guy on Earth and a guy moving in a spaceship at a very high speed.

Event A: a stopwatch on Earth displays t = 0 s
Event B: a stopwatch on Earth displays t = 30 s

So, on earth, T0 = 30
Let's assume the lorentz factor = 2

Doesn't this mean, then, according to the equation, that the guy on the spaceship measures 60 seconds between events A and B? Doesn't this mean that in the duration of 30 seconds passing on earth, 60 seconds has passed for the guy in the spaceship, meaning that the guy on the spaceship is aging faster than the guy on earth, completely counter to the established theory?

At the same time the observer on Earth sees the stopwatch of the spaceship record 30 seconds when his own watch records 60 seconds. Each sees the other's clock as running slower. This is the origin of the "twin's paradox" which is not really a paradox and can be resolved. There are many many threads on the twin's paradox here in this forum.

Tyrusaur said:
2. Lorentz Contraction Derivation

I understand that to derive the Lorentz contraction, you use

l0 = x2-x1 reference frame of earth
l = x2' - x1' reference frame of spaceship

so then, since x1 = L (x1' + vt')
x2 = L (x2' + vt')

you can write x2-x1 = L (x2'-x1')
So, l = l0/L, the Lorentz contraction formula.

My question is, why couldn't you have also used the reverse set of equations

x1' = L (x1-vt)
x2' = L (x2-vt)

to get x1'-x2' = L (x1-x2)
and then, in this case, l = l0 * L, which is the exact opposite result?


I think I'm probably thinking about this the wrong way, so if someone could give me some help that would be really appreciated.

Lo = x2 - x1 Length of rod on Earth as measured by Earth observer
L' = x2' - x1' Length of rod on Earth as measured by Spaceship observer

Gamma factor: y = sqrt(1-v^2/c^2) = 2

Lorentz tranformation equation: x' = (x-vt)*y as per ref http://en.wikipedia.org/wiki/Lorentz_transformation


L' = (x2' - x1') = ((x2-vt2) - (x1-vt1))*y -->

L' = (x2' - x1') = ((x2-x1) - vt1 + vt2)*y -->

In the Earth Frame say x2 = 8 and x1 =2 and t2=t1=3 then

L' = (x2' - x1') = (8-2 -3+3)*y = 6*y = 12

which is an incorrect result! What went wrong? The ends of the rod were measured simultaneously in the frame of the Earth observer at t1=t2=3 but those two events were not simultaneous in the frame of the spaceship observer. The relativity of simultaneity tells us that clocks in the other frame are out of sync according to to their displacement from the origin proportional to t+x*v/c^2 so we can rewrite the length contraction formula as:

L' = (x2' - x1') = ((x2-v(t2+x2*v/c^2)) - (x1-v(t1+x1*v/c^2)))*y -->

L' = (x2' - x1') = ((x2(1-v^2/c^2)-vt2) - (x1(1-v^2/c^2)-vt1))*y -->

L' = (x2' - x1') = ((x2/y -vt2) - (x1/y -vt1)) -->

L' = (x2' - x1') = ((x2-x1)/y -vt2 +vt1)) -->

L' = (x2' - x1') = (x2-x1)/y = (8-2)/2 = 3

which is now the correct result. The reason the inverse equation cannot be applied directly is that two events that are simultaneous in one frame are not simultaneous in other frame, so we cannot simply assume vt1=vt2 and cancel them out when looking from another frame.
 
  • #5
wow, thanks for the responses. they really cleared it up.
 

1. What is time dilation?

Time dilation is a phenomenon where time appears to move slower for an object or person that is moving at high speeds compared to an observer who is at rest. This is a consequence of Einstein's theory of relativity.

2. How does time dilation affect space travel?

Time dilation plays a crucial role in space travel as it causes time to pass slower for astronauts who are traveling at high speeds. This means that they age slower compared to people on Earth, and when they return, they will have aged less than their counterparts on Earth.

3. What is Lorentz contraction?

Lorentz contraction, also known as length contraction, is a phenomenon where an object appears shorter in the direction of its motion compared to an observer who is at rest. This is also a consequence of Einstein's theory of relativity.

4. How is Lorentz contraction related to time dilation?

Lorentz contraction and time dilation are two sides of the same coin. They are both consequences of the theory of relativity and are closely related. Time dilation affects the passage of time, while Lorentz contraction affects the length of objects in motion.

5. Can time dilation and Lorentz contraction be observed in everyday life?

Yes, time dilation can be observed in everyday life through experiments with high-speed particles or by comparing the time on synchronized clocks on airplanes and on the ground. However, Lorentz contraction is not as easily observable in everyday life as it requires objects to be moving at extremely high speeds, close to the speed of light.

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