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So I'm given a problem in which I have to prove an identity. It goes:

2csc2x=csc^2xtanx

I did the problem myself and could only get to 2csc2x=2\(sin2x)= 2\(2sinxcosx). I had no idea how to get further with the problem so I looked at the answer in the back of my pre-calculus book. It said that:

2\(2sinxcosx) = 1\(sin^2x) multiplied by sinx\cosx = csc^2xtanx

I don't understand the part that says 2\(2sinxcosx)= 1\(sin^2x) multiplied by sinx/cosx. Could someone please explain to me how 2\(2sinxcosx) equals that?

2csc2x=csc^2xtanx

I did the problem myself and could only get to 2csc2x=2\(sin2x)= 2\(2sinxcosx). I had no idea how to get further with the problem so I looked at the answer in the back of my pre-calculus book. It said that:

2\(2sinxcosx) = 1\(sin^2x) multiplied by sinx\cosx = csc^2xtanx

I don't understand the part that says 2\(2sinxcosx)= 1\(sin^2x) multiplied by sinx/cosx. Could someone please explain to me how 2\(2sinxcosx) equals that?

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