Question on Rotational Dynamics

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Homework Help Overview

The discussion revolves around a problem in rotational dynamics involving a uniform disc rotating on a rough surface. The original poster seeks to understand the time taken for the disc to come to rest and the variation of its kinetic energy with time.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants inquire about the work done by friction and the relevant formulas, with some discussing the relationship between kinetic energy, potential energy, and work. Others express the importance of showing prior work before receiving assistance.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the problem, including the calculation of work done by friction and the implications of the original poster's question. Guidance has been provided regarding the need for the original poster to demonstrate their efforts before receiving further help.

Contextual Notes

There is an emphasis on adhering to forum guidelines regarding homework assistance, highlighting the need for the original poster to show their work before others provide help.

alamin
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1.A uniform Disc of Radius R is rotating in its own plane with angular velocity w when it is placed flat on a rough table. If u the coefficient of sliding friction is independent of velocity show that the time taken for the disc to come to rest is
(3RW)/(4ug). How does the kinetic energy of rotation of the disc vary with time?
 
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ok please show us what work you have done. we arent going to solve (although we can) your problems for you
also for your problems remember that
[tex]\Delta K + \Delta U = W_{friction}[/tex]
where K represnets kinetic energy
U represnts potential energy
and W represents work
and delta is the change
 
May I know what is the formula to calculate work done by frcition? Displacement is given in the case, but the friction force is not.
 
work done is F d cos(angle)
if angular then d = (angular displacement)
 
stunner5000pt said:
work done is F d cos(angle)
if angular then d = (angular displacement)
I thought the work done by the friction force is [tex]\int \vec{\tau} \cdot d\vec{\theta}[/tex]?
 
Last edited:
Psi-String,

We appreciate that you are willing to assist, but please do not offer complete solutions to homework questions.

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On helping with questions: Any and all assistance given to homework assignments or textbook style exercises should be given only after the questioner has shown some effort in solving the problem. If no attempt is made then the questioner should be asked to provide one before any assistance is given. Under no circumstances should complete solutions be provided to a questioner, whether or not an attempt has been made.[/color]
 

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