Question on velocity at T1 and T2 problem

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SUMMARY

The problem involves calculating the velocity and position of a bus given its acceleration function a(t) = 1.23t. The initial conditions are the bus's velocity at time t = 1.05 seconds, which is 4.90 m/s, and its position at the same time, which is 6.09 m. To find the velocity at t = 2.01 seconds, one must integrate the acceleration function to derive the velocity function, then evaluate it at the specified time. The average acceleration formula provided is not applicable for this scenario.

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Homework Statement



The acceleration of a bus is given by a(t)=at where = 1.23 is a constant.
If the bus's velocity at time = 1.05 is 4.90 , what is its velocity at time = 2.01 ?
If the bus's position at time = 1.05 is 6.09 , what is its position at time = 2.01 ?

Homework Equations



a=v2-v1/t2-t1

The Attempt at a Solution


Tried to use that equation to solve for V2 and got 6.08 as my answer, however masteringphysics said I was incorrect
 
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njt84572 said:
The acceleration of a bus is given by a(t)=at where = 1.23 is a constant.
Something got left out in your cut and paste. Did you mean that a(t) = 1.23t ?
a=v2-v1/t2-t1
That defines average acceleration. Not useful here. (Unless I have guessed wrong about your problem.)

Instead, given the acceleration function how can you calculate a velocity function? Think calculus!
 

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