Question on Von Mises Stress Envelope

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The discussion focuses on the Von Mises Stress Ellipse and its application to a pipe subjected to radial, axial, and tangential stresses. It questions why a higher Von Mises stress is required for yielding in scenarios with both positive radial and axial stresses, as well as negative radial and positive axial stresses. The response highlights that shear stress, which is more detrimental to ductile materials, is greater in quadrants II and IV, influencing the yielding behavior. This indicates that the interaction of different stress types affects the overall yield strength of materials. Understanding these stress interactions is crucial for accurate material failure predictions in engineering applications.
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I have a question about the Von Mises Stress Ellipse:
http://upload.wikimedia.org/wikipedia/commons/4/48/Tresca_stress_2D.png

I understand that this equation if a component is subject to more than just an axial stress, the effect must be account for. I also understand that the ellipse is the result if setting one of the stresses to zero; the resulting equation is the equation for an ellipse.

Let's say that we have three stresses acting on a pipe: radial, axial, and tangential. Let's set tangential stress to zero.
-If you have positive radial (towards the center) and positive axial stress (tensile), why would you need a higher von-Mises stress to yield the pipe (see Quadrant I)?
-If you have negative radial (away from the center) and positive axial stress (compressive), why would you need a higher von-Mises stress to yield the pipe (see Quadrant III)?
 
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masshakar: Shear stress is higher in quadrants II and IV. Shear stress is relatively more detrimental than normal stress (quadrants I and III), for ductile materials.
 
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