Question on Von Mises Stress Envelope

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SUMMARY

The discussion centers on the Von Mises Stress Envelope and its application in analyzing stress states in materials, specifically pipes subjected to radial, axial, and tangential stresses. The participants explore the implications of setting tangential stress to zero and the resulting need for higher Von Mises stress to yield the pipe under different stress conditions. It is established that shear stress plays a critical role in determining yield strength, particularly in Quadrants II and IV, where it is more detrimental than normal stress in ductile materials.

PREREQUISITES
  • Understanding of Von Mises Stress theory
  • Familiarity with stress states: radial, axial, and tangential
  • Knowledge of shear stress effects on ductile materials
  • Basic principles of material yield criteria
NEXT STEPS
  • Research the derivation of the Von Mises Stress criterion
  • Study the impact of shear stress on ductile materials
  • Explore the Tresca criterion for yield strength comparison
  • Learn about finite element analysis (FEA) for stress evaluation in complex geometries
USEFUL FOR

Mechanical engineers, materials scientists, and students studying stress analysis in structural components will benefit from this discussion, particularly those interested in the behavior of ductile materials under complex loading conditions.

masshakar
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I have a question about the Von Mises Stress Ellipse:
http://upload.wikimedia.org/wikipedia/commons/4/48/Tresca_stress_2D.png

I understand that this equation if a component is subject to more than just an axial stress, the effect must be account for. I also understand that the ellipse is the result if setting one of the stresses to zero; the resulting equation is the equation for an ellipse.

Let's say that we have three stresses acting on a pipe: radial, axial, and tangential. Let's set tangential stress to zero.
-If you have positive radial (towards the center) and positive axial stress (tensile), why would you need a higher von-Mises stress to yield the pipe (see Quadrant I)?
-If you have negative radial (away from the center) and positive axial stress (compressive), why would you need a higher von-Mises stress to yield the pipe (see Quadrant III)?
 
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masshakar: Shear stress is higher in quadrants II and IV. Shear stress is relatively more detrimental than normal stress (quadrants I and III), for ductile materials.
 

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