Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Homework Help
Introductory Physics Homework Help
Question regarding basic dynamics and forces involved?
Reply to thread
Message
[QUOTE="Ascendant78, post: 4502083, member: 434818"] For starters, thanks for the feedback. As far as your suggestion, I am still at a loss. The total gravitational force of both the student and the chair (95kg) comes out to be 931N. So, in order for there to be an acceleration upwards (positive), the force of the rope would have to be greater than 931N, wouldn't it? When you multiply the acceleration by the total mass of the student and chair, it comes out to 67.45N. So, from what I was thinking, the 67.45N would be the additional N necessary to attain the acceleration above and beyond the 931N necessary to equal the gravitational force. Please tell me where my reasoning is wrong here, as I am still confused? [/QUOTE]
Insert quotes…
Post reply
Forums
Homework Help
Introductory Physics Homework Help
Question regarding basic dynamics and forces involved?
Back
Top