I Question regarding finding the magnitude of Torque

  • I
  • Thread starter Thread starter Harikesh_33
  • Start date Start date
  • Tags Tags
    Magnitude Torque
Click For Summary
The discussion focuses on calculating the torque of a system with two masses attached to a rod, which is rotating at an angle θ from the vertical. The key point raised is the definition of the vector r, which is the distance from the pivot point to the mass. The thread was closed for moderation, emphasizing that schoolwork-related questions should be posted in designated Homework Help forums. Additionally, users are reminded to attach images directly rather than using temporary links. The conversation highlights the importance of proper forum etiquette and guidelines for posting academic questions.
Harikesh_33
Messages
24
Reaction score
4
User has been reminded to post schoolwork-type questions in the Homework Help forums, and to upload images here rather than just linking to them.
TL;DR
https://imgur.com/a/JDUgrrZ

This is the question ,now there are two ways to approach this .

1)Using the formula τ=r×F .
2)Finding L and differentiating it.

Now I approached the problem with the first method .

Since the mass is moving along a circle of radius rsinθ,the centripetal force is F=mrsinθω² ....(1)

https://imgur.com/a/nZogpVO. ...(A)

Here r is the vector from the centre of rod (which is stationery ) to the mass .

Angle between r and F is 90°+θ .

Therefore Torque τ is rFsin(90+
Question regarding finding the magnitude of Torque of a system of two masses attached to a rod rotating at angle of θ degrees with respect to a vertical
 
Physics news on Phys.org
What are you considering r to be?

FA00FD8A-D2E0-4177-A22F-1DA48C4F3A08.jpeg

89801AFC-3C1E-4396-89C9-73AB6CAE1462.jpeg
 
The vector from point through which the rod is rotating to the mass .

I have drawn r Vector in second image .
 
Thread closed for Moderation...
 
Thread will remain closed here. @Harikesh_33 -- Please check your PMs. Schoolwork-type questions (even if for self-study) must be posted in the Homework Help forums. Also, please do not just transitory imgur links to the images -- those can disappear which makes your thread make no sense. Please use the "Attach files" link below the Edit window instead. Thank you.
 
Hello, I'm joining this forum to ask two questions which have nagged me for some time. I am in no way trolling. They both are presumed obvious, yet don't make sense to me. Nobody will explain their positions, which is...uh...aka science. I also have a thread for the other question. Yes, I'm questioning the most elementary physics question we're given in this world. The classic elevator in motion question: A person is standing on a scale in an elevator that is in constant motion...
Thread ''splain this hydrostatic paradox in tiny words'
This is (ostensibly) not a trick shot or video*. The scale was balanced before any blue water was added. 550mL of blue water was added to the left side. only 60mL of water needed to be added to the right side to re-balance the scale. Apparently, the scale will balance when the height of the two columns is equal. The left side of the scale only feels the weight of the column above the lower "tail" of the funnel (i.e. 60mL). So where does the weight of the remaining (550-60=) 490mL go...
Let us take the Ampere-Maxwell law $$\nabla \times \mathbf{B} = \mu_0\,\mathbf{J}+\frac{1}{c^2}\frac{\partial \mathbf{E}}{\partial t}.\tag{1}$$ Assume we produce a spark that is so fast that the ##\partial \mathbf{E}/\partial t## term in eqn.##(1)## has not yet been produced by Faraday’s law of induction $$\nabla \times \mathbf{E}=-\frac{\partial \mathbf{B}}{\partial t}\tag{2}$$ since the current density ##\mathbf{J}## has not yet had time to generate the magnetic field ##\mathbf{B}##. By...