Question regarding hybridization of Carbon

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SUMMARY

The hybridization of the carbon atom in the carbanion [CH3]- is sp3 due to the presence of a lone pair of electrons, which creates a tetrahedral geometry. Each carbon atom's hybridization can be determined by counting the number of electron domains, which include bonds and lone pairs. For example, in the methyl anion, the calculation is 3 single bonds plus 1 lone pair, resulting in 4 domains, leading to sp3 hybridization. This method can be applied to other molecules, such as carbon dioxide (C=O) and acetylene (H-C≡C-H), to determine their respective hybridizations.

PREREQUISITES
  • Understanding of basic atomic structure and electron configuration
  • Familiarity with molecular geometry concepts
  • Knowledge of hybridization theory
  • Ability to identify electron domains in molecules
NEXT STEPS
  • Research "Hybridization of Carbon Compounds" for detailed explanations
  • Study "VSEPR Theory" to understand molecular shapes and angles
  • Learn about "Electron Domain Geometry" to enhance understanding of hybridization
  • Explore "Examples of Hybridization in Organic Chemistry" for practical applications
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Chemistry students, educators, and anyone interested in understanding molecular structure and hybridization in organic compounds.

aleferesco
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The question that I have is regarding the hybridization of the Carbon atom in the molecule Carbanion
48.gif



[CH3]-

My question is

Why is the carbon atom in Carbanion hybridized to sp3 orbitals instead of sp2?
shouldn't it be sp2 since the carbon atom is only making 3 bonds with hydrogen?
please explain

any help is truly appreciated


http://www.chem.uh.edu/Courses/Thummel/Chem3331/Notes/Chap4/Image178.gif
 
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The carbon is sp3 because it still has a lone pair of electrons to account for, which actually take up more space than a fourth bond would. Therefore, the geometry is still tetrahedral, with the lone pair located at the top. Like I said before, lone pairs take up more space; that's why in your first picture the hydrogens are a bit cramped together.
 
ooo makes sense thanks


so does this mean that for everytime carbon is Hybridize do we have to account for the lone pair in order to determine if its is sp, sp2 or sp3?
 
You could think about it like this: to determine hybridization, count the number of electron domains and subtract 1, where a domain is either a bond (single, double, or triple) or a lone pair. For example, the methyl anion has 3 single bonds + 1 lone pair = 4 domains - 1 = 3 (sp3).

Another example is a double bonded oxygen (C=O). The oxygen has 1 double bond + 2 lone pairs = 3 domains - 1 = 2 (sp2).

Another example is a carbon in acetylene (or ethyne): H-C=C-H. Each carbon has 1 triple bond + 1 single bond = 2 domains - 1 = 1 (sp).

You can use this method for now, but in time you'll get good enough to identify the hybridization just by looking at the atom.
 
Can cabon anion have s2p3 hybridization
 
I will like anybody with any useful web address or link explainimg more about hybridization to please share it.
I would like to know more about hybridization.
 

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