Question regarding relative velocities

  • Thread starter Thread starter JoeWr18
  • Start date Start date
  • Tags Tags
    Relative
Click For Summary
SUMMARY

Larry drives east at 40 km/h while his twin brother Harry drives west at 30 km/h, creating a relative velocity of 70 km/h between them. When they are 42 km apart, a carrier pigeon flies at a constant speed of 50 km/h. The time taken for the twins to meet is 0.6 hours, during which the pigeon travels a total distance of 30 km. The solution confirms that calculating the pigeon's distance using relative velocities for each leg is unnecessary for this scenario.

PREREQUISITES
  • Understanding of relative velocity concepts
  • Basic knowledge of kinematics
  • Familiarity with the Galilean addition of velocities
  • Ability to perform distance, speed, and time calculations
NEXT STEPS
  • Study the principles of relative velocity in physics
  • Learn about kinematic equations and their applications
  • Explore advanced problems involving multiple moving objects
  • Review examples of real-world applications of relative motion
USEFUL FOR

Students studying physics, particularly those focusing on kinematics and relative motion, as well as educators looking for illustrative examples of velocity concepts.

JoeWr18
Messages
1
Reaction score
0

Homework Statement


Larry is driving east at 40 km/h. His twin brother Harry is driving west at 30 km/h toward Larry along the same straight road. When they are 42 km apart larry sends out a carrier pigeon, which flies at a constant speed of 50 km/h (all speeds relative to the earth) . The pidgeon flies to Harry, becomes confused and immediatley returns to Larry, becomes more confused and then flies back to Harry. This continues until the twins meet, ignoring turn around time, how far did the pigeon fly.


Homework Equations


I think its just simple gallilean addition of velocities, but there's a part of my thought process I'm doubting which I will outline below.


The Attempt at a Solution


Velocity of Larry relative to Harry= 70 km/h

Time taken for them to cover 42 Km: T= 42/70= 0.6 Hours

In this time the pigeon travels distance D= 0.6*50 = 30 km

Is it this simple or do i need to calculate the distance for each "leg" of the pigeons journey using its velocities relative to each of the drivers?

Thanks
Joe
 
Physics news on Phys.org
It is this simple although the other (long) way also works if you know what you're doing.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 17 ·
Replies
17
Views
4K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 14 ·
Replies
14
Views
7K
Replies
4
Views
1K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
12
Views
5K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 16 ·
Replies
16
Views
3K