Question Regarding Velocity-Time Graphs

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SUMMARY

The discussion focuses on analyzing a velocity-time graph for a train, specifically addressing the tasks of drawing position-time and acceleration-time graphs, as well as calculating the acceleration at t = 3.0 seconds. The calculated acceleration is confirmed to be 1 m/s², while the position-time graph is noted to be incorrect in its parabolic representation between 0 and 4 seconds. Participants emphasize the need for accurate graphing techniques to properly reflect the motion described by the velocity-time graph.

PREREQUISITES
  • Understanding of kinematic equations, specifically a = (Vf - Vi) / t
  • Familiarity with graphing techniques for position-time and acceleration-time graphs
  • Knowledge of basic physics concepts related to motion
  • Ability to interpret velocity-time graphs
NEXT STEPS
  • Study kinematic equations in-depth, focusing on their applications in motion analysis
  • Learn how to accurately draw position-time graphs from velocity-time data
  • Explore the relationship between velocity, acceleration, and time in physics
  • Practice graphing exercises using different motion scenarios to improve accuracy
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Students studying physics, educators teaching kinematics, and anyone interested in mastering graphing techniques related to motion analysis.

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Homework Statement



The figure below shows the velocity-time graph of a train that starts from the origin at t = 0s

5d714o.jpg


a) Draw a position-time graph and an acceleration-time graph for the train

b) Find the acceleration of the train at t = 3.0 s

Homework Equations



a = Vf - Vi / t

x = 1/2 at^2 + Vi x t + Xi


The Attempt at a Solution



a)
xfq3w6.jpg


b) 1 m/s^2

Do my answers look right? If not, what did I do wrong?
 
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The acceleration is correct, and the graph of x(t) is almost correct, only the part between 0 and 4 s does not look parabolic, and check x at t=2 s. ehild
 
Looks right to me. But those are really, really, truly, bad graphs.
 

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