A particle moves along the c axis. its position is given by the equation x = 2+3t-4t^2, with x in meters and t in seconds. Determine (a) its position when it changes direction and )b) its velocity when it returns to the position it had at t = 0.(adsbygoogle = window.adsbygoogle || []).push({});

i understand how to get (a) but for (b) im confused why in the solution they put -x = -2-3t+4t^2 why is the negative there, i understand there is a change in direction at 0, im confused why the negative sign is there can you give me a clear and understanding reasoning. thank you.

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# Homework Help: Question why is there a negative sign

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