Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
General Math
Calculus
Differential Equations
Topology and Analysis
Linear and Abstract Algebra
Differential Geometry
Set Theory, Logic, Probability, Statistics
MATLAB, Maple, Mathematica, LaTeX
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
General Math
Calculus
Differential Equations
Topology and Analysis
Linear and Abstract Algebra
Differential Geometry
Set Theory, Logic, Probability, Statistics
MATLAB, Maple, Mathematica, LaTeX
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Mathematics
Linear and Abstract Algebra
Questions about analysis of algorithm
Reply to thread
Message
[QUOTE="I like Serena, post: 6762768, member: 312166"] Aren't we subtracting $a\cdot h[j-(d'-d)]$ from $f[j]$, where $a=u\cdot f[i]$? And repeat for every value of $j$ (Wondering) So I think we're subtracting $f[i] \cdot u \cdot X^{i-d} \cdot (h[0],\dots,h[d])$ from $(f[0], \dots, f[d'])$. This is designed so that the coefficient of the highest power in $f$ becomes 0. And simultaneously we add an entry to $q$ so that $f+h\cdot q$ remains the same. I didn't say it quite right, since $r$ only gets a value at the very end. Initially we have $f_{original}=f+h\cdot q$, since $q=0$ at this time. Then in each step we find another entry in $q$ (the quotient) and modify $f$ accordingly. That is, we subtract a polynomial from $f$ such that the coefficient of its highest power becomes 0. And finally, the remaining value of $f$, that now has a lower power than $h$, is assigned to $r$ (the remainder). (Thinking)[/i][/i] [/QUOTE]
Insert quotes…
Post reply
Forums
Mathematics
Linear and Abstract Algebra
Questions about analysis of algorithm
Back
Top