Questions about spherical conductor

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A charge Q placed at the center of a neutral conducting spherical shell creates specific electric field conditions. Inside the shell (R < R1), the electric field is solely due to the charge Q. Between the inner and outer radii (R1 < R < R2), the electric field is zero, as expected within a conductor. Outside the shell (R > R2), the electric field is again influenced only by the charge Q, since the shell has no net charge. The discussion raises questions about charge distribution on the inner and outer surfaces of the conductor, emphasizing the relationship between charge density and surface area.
Niles
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Homework Statement


A charge Q is placed at the center of a conducting spherical shell of inner radius R1 and outer radius R2. The sphere has no net charge.

Ok, I have some statements for this setup. Would you be kind to check them?

The Attempt at a Solution



1) The electric field in a distance R < R1 from the pointcharge Q is the electric field coming from the charge itself.

2) The electric field in a distance R1 < R < R2 is zero (E-field zero inside a conductor always).

3) In a distance R > R2 the electric field is only coming from the point charge, since the conductor has no net charge.

4) The formula for the electric field outside a conductor: E = (sigma/epsilon_0)n. Does this only apply to the outside surface of a conductor, or also the inside surface? (In this case the inside-surface of the spherical shell)
 
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If one puts a charge Q (assumed positive) in the center of a spherical 'conductor', what happens to the charges in the conductor (which if neutral, has a balance of - and + charges)?
 
The positive charges go to the outer surface and the negative charges go to the inner surface.
 
What can one say about the charge densities of the inner and outer surfaces?
 
Charge-density is the charge per area, and since the charge is the same with different sign, I guess the only thing that makes them vary is the area.
 
what's the definition of a conductor?
Regards,.
Reilly Atkinson
 
The electric field inside is zero?

Am I way off with my answers in #1?
 
1, 2, and 3 look good to me. I'd have to think (more than I have time for at the moment!) about #4.
 

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