Questions on the basic principles of physics.

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Homework Help Overview

The discussion revolves around basic principles of physics, specifically focusing on concepts such as velocity, gravitational acceleration, and equations of motion. Participants are exploring the definitions and units associated with these concepts.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the units of velocity and discussing the value of gravitational acceleration, denoted as "g". There are attempts to clarify the distinction between "G" and "g", as well as the appropriate equations for calculating acceleration from distance and time.

Discussion Status

The conversation is ongoing, with various interpretations of the principles being explored. Some participants provide definitions and examples, while others seek clarification on specific points. There is no explicit consensus, but multiple lines of reasoning are being examined.

Contextual Notes

Participants are navigating potential misunderstandings regarding the units of measurement and the conversion between different units, particularly in the context of gravitational acceleration. There is also mention of using online tools for unit conversion.

MoreZitiPlease
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Really isn't involving problems, just principles of physics.


What are the units of velocity?

Im aware of m/s, but I hear there are more.

What is the value of "G"?

If an object starts from rest and travels a distance d in t sec, what equation may be used to find its acceleration?


Really all I need help on.
 
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MoreZitiPlease said:
Really isn't involving problems, just principles of physics.


What are the units of velocity?

Im aware of m/s, but I hear there are more.

What is the value of "G"?

If an object starts from rest and travels a distance d in t sec, what equation may be used to find its acceleration?


Really all I need help on.

Average velocity is the change in unit distance per the change in unit time. (m/s, mph, feet/sec. km/h, etc).

Instantaneous velocity is the rate of change in position per the rate of change per unit time. Same units.

The value of g is 9.8 [tex]\frac{m}{s^2}[/tex] or 32.2 [tex]\frac{ft}{s^2}[/tex]

Equation of motion:

[tex]x=x_0+vt+\frac{1}{2}at^2[/tex] Solve for a
 
Hey, I made a new thread.

I don't think you properly understood the question.

See my new thrad.
 
And I know the value of G is 9.8 we

but It would be 980cm/m2

right
 
MoreZitiPlease said:
And I know the value of G is 9.8 we

but It would be 980cm/m2

right

Centimeters per meter-squared? No. In centimeters, it would be [tex]\frac{cm}{s^2}[/tex]
 
Velocity could be measured in any distance units divided by any time units.

The acceleration caused by Earth's gravitational field, at the surface of the Earth, is normally denoted by g (not G) and is 9.81 meters per second per second.

If your object is accelerating at a constant rate then the equation to use is
d = 0.5 at^2
a = 2d / t^2
 
Yra I know it is 9.80 meters, but they want to convert it into centimeters. So it would b 980?
 
MoreZitiPlease said:
Yra I know it is 9.80 meters, but they want to convert it into centimeters. So it would b 980?


Yes. Use google as a calculator. Put in the following "9.8 meters to cm", click "search" and you get out the following: 9.8 meters = 980 centimeters

It even does automatic unit conversions. Put in "9.8 m + 32.2 ft", click "search and get back:

(9.8 meters) + (32.2 feet) = 19.61456 meters

How about this:

"50 mph + 10 m/s" "search"

(50 mph) + (10 (m / s)) = 32.35200 m / s

Pretty damn cool, huh?
 
Velocity is loosely a change in a position (distance) divided by the time interval that it took to change position.

So it will always be a distance over a time. Big G is called the gravitational constant( [tex]6.673*10^-11 \frac{m^3 s}{kg}[/tex]). Little g is acceleration due to gravity ([tex]GM/R^2[/tex]). On the surface of the Earth we can roughly measure it to (9.80m/s^2)
 

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