# Questions regarding relativistic momentum

1. Dec 11, 2011

### nos

Hi everyone,

http://en.wikibooks.org/wiki/Special_Relativity/Dynamics

I understand it all the way through, except the point where they have come to this equation.

m$_{red} =$$\frac{m_{blue}}{\sqrt{1-(\frac{u(x,r)}{c})^{2}}}$

Where(as I understand correctly) mblue is the mass according to the frame moving at the same x-velocity as the blue ball and where mred is the mass of the red ball according to the frame moving with the same x-velocity as the blue ball.

Then they go to:

M =$\frac{m_{0}}{\sqrt{1-(\frac{u}{c})^{2}}}$

Where u is now the relative velocity of the red ball for the moving frame.
But that is what I don't understand. How can they suddenly ignore the relativistic effects of the y-velocities? The first equation gives the mass of red ball in terms of the relative x-velocity of the red ball. Then how do they get to relativistic mass in terms of the relative velocity u? Because ux,red is only the x component velocity and ured has both a x-component and y-component.

This is my hypothesis:

They let both uy,red and uy, blue approach zero. So that the mass of the blue ball will correspond to the rest mass and that the relativistic effects of the y-velocities will cancel.

Thank you.

Last edited: Dec 11, 2011
2. Dec 11, 2011