Quick acceleration word problem

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SUMMARY

The discussion focuses on solving a physics problem involving an electron's motion under constant acceleration. The initial speed is 3.0 x 105 m/s, and the acceleration is 8.0 x 1014 m/s2. To find the time required to reach a final speed of 5.4 x 105 m/s, the correct calculation yields T = 3 x 10-18 seconds. For distance traveled, participants recommend reviewing equations of motion with constant acceleration to derive the solution.

PREREQUISITES
  • Understanding of kinematic equations for constant acceleration
  • Familiarity with basic physics concepts such as velocity and acceleration
  • Ability to perform arithmetic operations with scientific notation
  • Knowledge of the relationship between distance, rate, and time
NEXT STEPS
  • Review kinematic equations for motion with constant acceleration
  • Learn how to derive time and distance from acceleration and velocity
  • Practice problems involving electron motion under varying acceleration
  • Explore advanced topics in classical mechanics related to particle dynamics
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Students studying physics, particularly those focusing on kinematics and motion under constant acceleration, as well as educators seeking to clarify these concepts.

joe215
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Homework Statement


An electron has an initial speed of 3.0 x10^5 m/s. It undergoes an acceleration of 8.0 x 10^14 m/s/s. (a) How long will it take to reach a speed of 5.4 x 10^5 m/s? (b) How far will it have traveled in this time?


Homework Equations



Rate x Time= Distance



The Attempt at a Solution



A. R x T= D

(8.0 x 10^14 m/s/s)(T)=(5.4 x 10^5 m/s)-(3.0 x10^5 m/s)

T= 3x10^18 seconds

B. How do you find the distance traveled? This is stumping me for some reason.


Thanks!
 
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Assuming the magnitude of acceleration is correct, that's a huge acceleration.

The T should be quite small.

What is the relationship between the change in velocity, acceleration and time?
 
Joe has the correct relation, even if the terminology is a bit odd ("Distance" is really change in velocity, "Rate" is acceleration). He just needs to carefully redo the arithmetic given by that relation.

Part B: your textbook has 3 or 4 equations for motion with a constant acceleration. Look over them, and choose one which can be solved for distance using the given information.
 

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