A 900N force acts on a 5kg box in horizontal direction initially at rest. When V=6m/s the force stops. Through what distance was the block pushed. I said this: F=ma v=x/t ---> t=x/v (1) a=v/t (2) combine (1) and (2) a=v^2/x So x=v^2/a That is the same as angular circular motion. Then there is x=0.5at^2 With t=x/v x=0.5a(x/v)^2 1=0.5ax/v^2 2=ax/v^2 x=(2v^2)/a Where am I screwing up? Thank you for your time.