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Through what distance was the block pushed.

I said this:

F=ma

v=x/t ---> t=x/v (1)

a=v/t (2)

combine (1) and (2)

a=v^2/x

So x=v^2/a

That is the same as angular circular motion.

Then there is

x=0.5at^2

With t=x/v

x=0.5a(x/v)^2

1=0.5ax/v^2

2=ax/v^2

x=(2v^2)/a

Where am I screwing up?

Thank you for your time.