Solve for Bmax: Quick Faraday Equation with Transformer Parameters

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SUMMARY

The discussion focuses on calculating the maximum magnetic flux density (Bmax) using the Faraday equation for a transformer. Given the parameters: V1 = 10V (20V peak-to-peak), N1 = 40 turns, f = 5000Hz, and A = 76x10-6 m2, the correct voltage to use in the equation is the peak voltage. The calculation yields Bpeak = 0.104 Tesla when substituting the values into the formula Bpeak = Vpeak / (2πfAN).

PREREQUISITES
  • Understanding of Faraday's Law of Electromagnetic Induction
  • Basic knowledge of transformer parameters (voltage, turns, frequency, area)
  • Familiarity with Tesla as a unit of magnetic flux density
  • Ability to perform calculations involving exponential notation
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  • Learn about the effects of frequency on transformer performance
  • Explore the relationship between peak voltage and RMS voltage in AC circuits
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Electrical engineers, students studying electromagnetism, and professionals involved in transformer design and analysis will benefit from this discussion.

kishanpatel50
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I have this equation and the following values for a transformer

Bmax= (V1)/(4N1fA)

V1=10v, i.e. 20v peak-to-peak
N1=40 turns
f=5000Hz
A=76x10-6 m2

When i substitute in the voltage, do i use the 10v, or the peak to peak, or would i have to convert to Vrms
 
Last edited:
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the Faraday equation is

Vpeak= (2 pi f) Bpeak A N

So Bpeak= 10/(6.28 f A N) = 0.104 Tesla
 

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