Solenoid vs transformer inductance

In summary: However, in more recent texts, these calculations are relegated to appendixes or relegated to a "permeability" section.This is where the "universal transformer equation" comes in-it provides a concise way to calculate inductance in a magnetic circuit.But what if I want to estimate the actual current in the primary. Then I will need to calculate L.And it turns out to be tricky. In addition to the permeability that varies with current, I am not even sure what formula for L I should use.Imagine you learn for years F=ma and other fundamental stuff that is based on /derived from other stuff and then they tell you meh these only work for some ideal model.Welcome
  • #1
xopek
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When they teach transformers, they give you the Ampere's law, the Faraday's law, etc. and then derive this well known formula L = μ * N^2 * A / ℓ. And everything is no nice, all these parameters are used to define some other relationships, like the concept of reluctance in magnetic circuits, etc. But it turns out that this formula may only be valid for long single layer solenoids with the coil length >> D. And for multilayer solenoids there are tons of different numeric methods. But I've never seen them discussed in the context of iron core transformers. So how come the well known relationships between Ф, B, A, H, I, E, ℓ etc. captured in various famous laws yield an unusable formula for inductance? For practical purposes, they just give you a universal transformer equation and tell you here is how you calculate the number of turns in the primary to avoid saturation. But what if I want to estimate the actual current in the primary. Then I will need to calculate L. And it turns out to be tricky. In addition to the permeability that varies with current, I am not even sure what formula for L I should use. Imagine you learn for years F=ma and other fundamental stuff that is based on /derived from other stuff and then they tell you meh these only work for some ideal model.
 
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  • #2
Welcome to the real world.
You'll discover most of your textbook problems were set up to solve readily without the extra complications you mention.

A transformer has a closed magnetic circuit so your formula above will work pretty well.
A solenoid or motor has an air gap
so you must calculate reluctance of each piece of the magnetic circuit
and solve it as a a system.

If you take a course in electrical machinery it should get you past your immediate hurdle

you might also look for a book titled "Inductance Calculations", it'll address weird geometries

xopek said:
So how come the well known relationships between Ф, B, A, H, I, E, ℓ etc. captured in various famous laws yield an unusable formula for inductance?
They get you started. That's their purpose.

Life is difficult. This is a great truth, one of the greatest truths. It is a great truth because once we truly see this truth, we transcend it. Once we truly know that life is difficult-once we truly understand and accept it-then life is no longer difficult. Because once it is accepted, the fact that life is difficult no longer matters.
- m scott peck
 
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  • #3
jim hardy said:
A transformer has a closed magnetic circuit so your formula above will work pretty well.

OK, this sounds really reassuring. That would explain why just this formula is discussed in the context of iron core transformers! It just drove me crazy that one could combine the Ampere's law with the Faraday's law and rearrange things a bit, solve for this, solve for that, and finally get the expression for L, and then have doubts about validity of that formula since it is not even used in some cases. Sometimes these things just don't connect in my mind. I've seen some calculators based on the Maxwell's elliptic integral formula and they basically calculate mutual inductance between every pair of turns. And what I noticed is the more "compact" coils (shorter length more layers) are predicted to have higher inductance than longer coil with fewer layers. So that threw me off and I was afraid that in case of transformers that might also hold true and that would make the universal transformer equation less useful as the number of layers/turns per layer would have to be taken into account. But I never thought of it from the perspective of an air gap vs a closed magnetic circuit.
 
  • #4
xopek said:
So that threw me off and I was afraid that in case of transformers that might also hold true and that would make the universal transformer equation less useful as the number of layers/turns per layer would have to be taken into account.

Things are simplified to convey the basics.
In a real transformer that's heavily loaded there are opposing mmf's that force some flux outside the iron core .
As designers push harder to minimize the amount of material in a product, those complex analyses let them eke out the last few drops of performance.
Armed with a good understanding of your basics you'll be able to handle the tedious calculations for those more complete solutions.
I forgive educators for simplifying, they have a lot to cover in a little time and humans can learn at only a finite rate.

You'll find old textbooks from prior to 1950 have good nuts&bolts explanations with graphical solutions.
 
  • #5


I can understand your confusion and frustration with the discrepancies between the well-known formula for inductance and its practical application in transformers. It is true that the formula L = μ * N^2 * A / ℓ is derived from fundamental laws and relationships, but it is important to remember that it is an idealized formula for a long single layer solenoid.

In practical applications, such as transformers, there are many other factors that come into play, such as the geometry of the coils, the material properties of the core, and the behavior of the magnetic field. These factors can greatly affect the inductance and make it difficult to accurately calculate using the idealized formula.

In addition, as you mentioned, the permeability of the core material can also vary with current, making it even more challenging to calculate the inductance. This is why, in practical applications, a universal transformer equation is often used to estimate the number of turns in the primary to avoid saturation. This equation takes into account all the complex factors that affect inductance and provides a more accurate estimation for practical purposes.

It is important to keep in mind that while the fundamental laws and relationships are essential for understanding the principles behind inductance, they may not always provide an accurate representation of real-world applications. As scientists, we must constantly adapt and refine our understanding as we encounter new challenges and complexities.
 

1. What is the difference between a solenoid and a transformer?

A solenoid is a coil of wire that produces a magnetic field when an electric current is passed through it. A transformer, on the other hand, is a device that uses two or more coils to transfer electrical energy between circuits through electromagnetic induction.

2. How does the inductance of a solenoid compare to that of a transformer?

The inductance of a solenoid is typically much lower than that of a transformer. This is because a solenoid has a single coil, whereas a transformer has multiple coils that are often wound around a magnetic core, increasing the inductance.

3. Which one has a higher self-inductance: a solenoid or a transformer?

A transformer usually has a higher self-inductance than a solenoid. This is because the multiple coils in a transformer increase the magnetic flux and thus the inductance, whereas a solenoid has a single coil and a lower magnetic flux.

4. How does the inductance of a solenoid or transformer affect its performance?

The inductance of a solenoid or transformer affects its performance in terms of its ability to store and transfer electrical energy. A higher inductance allows for a larger energy storage and transfer, but it also leads to slower response times and more power losses.

5. Can a solenoid be used as a transformer or vice versa?

In some cases, a solenoid can be used as a transformer by adding a magnetic core and multiple coils. However, a transformer cannot be used as a solenoid as it lacks the necessary single coil configuration.

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