Find an expression for the acceleration of m1.
The Attempt at a Solution
I did this earlier, and looking back on it I have a question:
Sum of forces for m1:
Fx= F2 on 1= m1a1
Sum of forces for m2:
Fy = F1 on 2 + T1 - m2g = m2a2
I got the expression after substituting them into each other and saying a2 = -.5a1, I'm just wondering why you can say T1= F1 on 2 , because since there is acceleration, can you consider the tension throughout the rope to be the same?