The problem involves determining the equation of a line that passes through the points (-3, 5) and (1, -3). The original poster presents an equation derived from these points and seeks clarification on the simplification process to arrive at the final equation.
Participants are navigating through the steps of algebraic manipulation, including dealing with double negatives and isolating variables. There is an emphasis on ensuring clarity in the transformation of the equation.
JonF said:y - 5 = -2(x-(-3) ) Does NOT turn into y - 5 = -2x + 3?
Deal with the double negative first, then distribute the -2 to ALL terms it’s multiplied by, so:
y - 5 = -2(x-(-3) ) -> y - 5 = -2(x+3) -> y - 5 = -2x-6 -> y= -2x-1
You're not getting rid of y - 5 - you're just isolating y to get it all by itself. Yes, you add 5 to both sides.nukeman said:wow, thanks. That makes much more sense!
ok so y - 5 = -2x-6
now you to get rid of the y - 5, you ad 5 to both sides correct?
nukeman said:y= -2x-1