(adsbygoogle = window.adsbygoogle || []).push({}); Quick question about Equilibrium w/ Stress :D

Hello guys!

I am new here but I plan to stick around for a long time :D

I have a quick question, and I was wondering if you guys could help me...

1) A steel cable with cross sectional area 3.0 cm^2 has an elastic limit of 2.4*10^8Pa. Find the maximum upward acceleration that can be given a 1200-kg elevator supported by the cable if the stress is not to exceed one-third of the elastic limit.

Answer is 10.2 m/s2.

This is what I did :D,

1/3 of 2.4*10^8 is 80000000Pa

Tensile Stress=F/A

80000000Pa=F/.03m

F=2400000

F=Ma

2400000Pa/1200kg=a

a=2000m/s^2

Anyone? It's late so I gave it my best shot :D

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# Homework Help: Quick question about Equilibrium w/ Stress

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