Quick question about Equilibrium w/ Stress

[ovoleg]

Quick question about Equilibrium w/ Stress :D

Hello guys!

I am new here but I plan to stick around for a long time :D

I have a quick question, and I was wondering if you guys could help me...

1) A steel cable with cross sectional area 3.0 cm^2 has an elastic limit of 2.4*10^8Pa. Find the maximum upward acceleration that can be given a 1200-kg elevator supported by the cable if the stress is not to exceed one-third of the elastic limit.
Answer is 10.2 m/s2.

This is what I did :D,
1/3 of 2.4*10^8 is 80000000Pa

Tensile Stress=F/A

80000000Pa=F/.03m
F=2400000

F=Ma
2400000Pa/1200kg=a
a=2000m/s^2

Anyone? It's late so I gave it my best shot :D

 

[Fermat]

1cm² = (0.01)² m² = 0.0001 m²

 

[ovoleg]

1cm² = (0.01)² m² = 0.0001 m²

With that I get 2m/s^2(Which you are right, I didn't see that initially)

Using N2L, T-W=Ma
So, T=F from above?
F-mg=ma
24000N-11760N=1200kg*A
A=10.2m/s^2

Thanks a bunch L:D