Question about stress and strain

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SUMMARY

The discussion centers on calculating the minimum diameter of a wire made from a material with an elastic limit of 1.6 x 108 Pa, capable of supporting a load of 100 N without exceeding this limit. The relevant formula used is stress (S) = force (F) / area (A), where area is defined as A = π(d/2)2. By substituting the known values into the equation, users can derive the necessary diameter for the wire.

PREREQUISITES
  • Understanding of basic physics concepts such as stress and strain
  • Familiarity with the formula for calculating stress (S = F/A)
  • Knowledge of geometric formulas for the area of a circle (A = πr2)
  • Ability to manipulate algebraic equations to solve for unknown variables
NEXT STEPS
  • Calculate the diameter of a wire using the formula S = F/A with given parameters
  • Explore the concept of elastic limit in materials science
  • Learn about different materials and their respective elastic limits
  • Investigate the effects of load on wire diameter and material selection
USEFUL FOR

Students in physics or engineering courses, materials scientists, and anyone involved in mechanical design or structural analysis will benefit from this discussion.

hoyy1kolko
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Homework Statement


The elastic limit for a type of material is 1.6 x 10^8 Pa.Determine the minimum diameter if a wire which is made of this material so that it can support a load of 100N without the stress exceeding the elastic limit.


Homework Equations


elastic limit=stress
=F/A
1.6 x 10^8=100/ (pie)d^2
I can't get the answer.please help

The Attempt at a Solution

 
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In your S = F/A formula, replace A with the area of the circular wire.
Solve for the radius or diameter.
Put in the numbers for S and F.
 

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