Quick question about power lines and E=IxR

[Lavid2002]

Ok so I have read that power lines carry very high voltage to minimize loss through resistance, but when I take a look at the formula

E=IxR
E=Voltage
I=Current
R=Resistance

Divide both sides to get

E/I=R

To minimize R we should make the numerator of the quotient smaller, and the denominator larger (I.E. 1/1,000,000) To get a small value for R right?

This would in turn, mean cranking up the current, and lowering the voltage

I know I am wrong, as the companies get good results from cranking up the voltage. I can't find my error though.

Thanks Guys :D

-Dave

 

[Bob S]

The power loss is actually I²R, so minimizing current minimizes losses.

 

[Curl]

R is fixed, a material property of the aluminum/iron that the wires are made of. You are minimizing power loss as Bob S said.