Quick question for Finding EOM with diff eq

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SUMMARY

The discussion centers on finding the equation of motion for a system where acceleration is defined as a = -bv, with b as a constant and v = v(t). The user successfully integrated the acceleration to obtain the velocity equation v = v0e-bt but encountered discrepancies when integrating to find the position x. The correct position equation is x = x0 + (v0/b)(1 - e-bt), which aligns with the derivative yielding the velocity. The user was advised to control the signs and consider the definite integral in their calculations.

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JaDi13
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I have been going through my old books again, and found myself a little stuck. I am not entirely sure if this would be better in this one or diffy eq.
The problem starts with having you find equation of motions when a= -bv, where b is constant and v = v(t)

Using method of separable equations, I was able to integrate the acceleration to get the velocity, v = v0e-bt

The problem is when I try to find the equation for x.
When I integrate v, using u substitution, I get x = (v0/b)e-bt+x0
The books says the answer x = x0 + (v0/b)(1-e-bt)
Also when I take the derivative of the book's answer, I get what I found for v

Am I way off base? Did I miss a step?
 
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JaDi13 said:
I get ##x = (v_{0}/b)e^{-bt}+x_{0}##

because this is wrong ... , the integral ##x=\int_{0}^{t}v_{0}e^{-bt}dt+x_{0}\not=\frac{v_{0}}{b}e^{-bt}+x_{0}##
control the signs! (and also the definite integral ...)
Ssnow
 

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