Quick question on Mathematical Induction

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Discussion Overview

The discussion revolves around the application of mathematical induction when dealing with statements involving two variables, specifically positive integers and real numbers. Participants explore how to handle the second variable in the induction process.

Discussion Character

  • Technical explanation, Conceptual clarification

Main Points Raised

  • One participant questions whether to treat the second variable, x, as a constant or to manipulate it similarly to the integer variable n during the induction proof.
  • Another participant suggests that x should remain as it is, since it is an arbitrary real number greater than or equal to -1, and emphasizes the importance of this condition in the proof.
  • A participant provides an example illustrating the relationship |x^n| = |x|^n for every positive integer n and real number x, indicating a specific case of the discussion.
  • Another participant mentions that for any given n, x can be shown to work, implying a potential understanding of the induction process with respect to the two variables.
  • One participant shares their experience of successfully applying the method in several examples, indicating a positive outcome without further elaboration.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the treatment of the variable x in the context of mathematical induction, with differing views on whether it should be manipulated like n or left as is.

Contextual Notes

Some limitations include the lack of specific examples or proofs to illustrate the points made, as well as the dependence on the definitions of the variables involved.

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In mathematical Induction, sometimes two variables are given, such as:
"All positive integers n and all real numbers x >= -1."

My question is do you solve this normally and just keep x as itself or do you have to expand it like you do with n, making it k + 1 etc etc.

Thanks in advanced
 
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You leave $x$ as it is, it is an arbitrary real number >= -1. In the proof it is like that you will need the fact x >= -1.
A little more context would help, but if I am guessing your issue correctly the answer is no.
 
Well an example would be:

|x^n| = |x|^n for every positive integer n and real number x.
 
You show for any given n, x works.

Which kind of makes sense, don't you think?
 
I have done a few examples and they all worked nicely.

Thanks.
 

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