Understanding Voltage in a Simple Circuit: A Quick Question

  • Thread starter Thread starter EvLer
  • Start date Start date
  • Tags Tags
    Voltage
Click For Summary
SUMMARY

This discussion clarifies the understanding of voltage in simple circuits, specifically regarding the voltage drop across resistors and inductors. The voltage drop from point A to B in the first circuit is correctly identified as the voltage across R2. In the second circuit configuration, the total voltage drop from A to B is the sum of the voltages across R1 and the inductor, confirming that current divides between the inductor and R2. The application of Kirchhoff's Voltage Law (KVL) is essential in analyzing these circuits.

PREREQUISITES
  • Basic understanding of Ohm's Law
  • Familiarity with Kirchhoff's Voltage Law (KVL)
  • Knowledge of series and parallel circuit configurations
  • Concept of voltage drops across resistors and inductors
NEXT STEPS
  • Study the application of Kirchhoff's Laws in complex circuits
  • Learn about the behavior of inductors in AC circuits
  • Explore voltage dividers and their applications in circuit design
  • Investigate the effects of resistance and inductance on circuit performance
USEFUL FOR

Electronics students, electrical engineers, and hobbyists interested in circuit analysis and design will benefit from this discussion.

EvLer
Messages
454
Reaction score
0
Hi all, I am asking to see if I understand voltage correctly:
This is what circuit looks like:
Code:
-----R1---A----R2---
|           +      |
Vs         v(t)    |
|           -      |
|_________B_______ |
As I see it, v(t)(voltage drop from A to B) is voltage across R2, is it correct?
Thank in advance.
 
Physics news on Phys.org
that is correct
 
What? the sum of the voltage drop from R1 and R2 is equal to the EMF (battery).
 
Didn't want to start another thread, but now I have another question: after the switch in some circuit moves to a certain position I get following circuit:
Code:
 A-------R1--------------
                |        |
                |        |
             indctr     R2
                |        |
                |        |
 B-----------------------
Then voltage drop from A to B is sum of voltages across R1 and inductor (or R2), right? Then there is a current coming from A and divides into 2 (for inductor and R2)? Or does R1 not have any current?
Thanks again.
 
Last edited:
drop from A to B is Vr1 and 2*Vr2. Even though the inductor and r2 voltages are the same, they both must be added.
 
Why 2*VR2? they are in parallel. What am I missing here? Don't inductor and R2 follow KVL?
 
oops, my bad. youre right. its just one.
 
Oh, Ok, thanks!
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
Replies
9
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
Replies
3
Views
2K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
5
Views
679
  • · Replies 1 ·
Replies
1
Views
794
  • · Replies 10 ·
Replies
10
Views
2K