Quiz 1: Testing Your Knowledge of Force & Inertia

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SUMMARY

The discussion revolves around solving a physics quiz focused on force and inertia, specifically analyzing forces in a diagram. Participants discuss calculating force components, with one user providing calculations for Fx and Fy, resulting in 7.5N and 13N respectively. Another user attempts to solve for tension (T1 and T2) using trigonometric relationships, arriving at T1=3.464 and T2=1.232. The conversation emphasizes the importance of understanding vector resolution and Newton's second law in solving equilibrium problems.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of vector resolution and trigonometry
  • Familiarity with force diagrams and free-body diagrams
  • Concept of equilibrium in physics
NEXT STEPS
  • Study vector resolution techniques in physics
  • Learn about free-body diagrams and their applications
  • Explore Newton's second law and its implications in equilibrium
  • Practice solving problems involving tension in systems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators seeking to enhance their teaching methods in force and inertia concepts.

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http://physicsed.buffalostate.edu/c...anics/PDF files/4-FP-Inertia/Tests/Quiz 1.pdf

1) I don't know how to do this, but I know there is the force of gravity by the Earth in the force diagram..

2) For this one I got the answer
Fx=7.5N [I did 1/2(15N) which equals 7.5 N]
Fy=13N [I took my x component 7.5N and I did 7.5sqrt3=13N]
Did I solve this problem right??

3) How do you write an equation for this diagram?

Can you tell me if I did the Bonus right?

T1cos(60)=T2
T2sin(60)= 3kg

T1sin(60)=3kg
I divided both sides by sin(60) to make T1 by itself so
T1sin(60)/sin(60)=3.464
SO T1=3.464

I took T1=3.464 and plug it into T1cos(60)=T2
3.464cos(60)=T2
T2=1.232

So I don't know if I got that one right??
My answer is T1=3.464 and T2=1.232

Please help me..I really need this. Thank you!
 
Physics news on Phys.org
1) There is also a normal force and a kinetic frictional force.
2) You need to resolve your vector into components using trig.
3) The system seems to be in equilibrium, so

F_{xnet}=0

and

F_{ynet}=0

Start from there and re-think your strategy for the bonus part. For one, tension is a force so you can't measure it in kg...Remember Newton's second law.
 

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