R-Squared Difference when Dependent variable is $/lb vs Total Dollars?

stats1322
Messages
2
Reaction score
0
Why would I see a fairly significant difference in r-square (98.5% vs 85%) when I change my dependent variable from Total $'s to $'s per lb? My independent variable in both cases is weight. Each equation yields essentially the same answer in all tests of weight (within .08%).

How do I know which one best represents my data? It makes a difference when talking to management if something explains all but 1.5% of the variation in price, vs 15%.
 
Physics news on Phys.org
Example of the difference...

A part that weighs 2 pounds:
Total dollars equation estimates $72.645
$/lb equation estimates $36.33/lb (36.33*2 = $72.66)

This is how it looks for all the different parts.
 
Last edited:
Namaste & G'day Postulate: A strongly-knit team wins on average over a less knit one Fundamentals: - Two teams face off with 4 players each - A polo team consists of players that each have assigned to them a measure of their ability (called a "Handicap" - 10 is highest, -2 lowest) I attempted to measure close-knitness of a team in terms of standard deviation (SD) of handicaps of the players. Failure: It turns out that, more often than, a team with a higher SD wins. In my language, that...
Hi all, I've been a roulette player for more than 10 years (although I took time off here and there) and it's only now that I'm trying to understand the physics of the game. Basically my strategy in roulette is to divide the wheel roughly into two halves (let's call them A and B). My theory is that in roulette there will invariably be variance. In other words, if A comes up 5 times in a row, B will be due to come up soon. However I have been proven wrong many times, and I have seen some...
Back
Top