Radiation heat transfer between air or wall

Click For Summary
SUMMARY

The discussion centers on the modes of heat transfer involving a hot object at 500K in a chamber with wall temperature at 300K and surrounding air at 320K. The heat transfer rate is expressed as q = q(conv) + q(rad), where convection occurs between the object and surrounding air, while radiation primarily occurs between the object and the chamber walls. The formula for net radiation heat transfer is qnet = Aσε(T^4 - Ta^4 - Tw^4), indicating that radiation from the air is insignificant compared to that from the walls. The conversation also touches on convective heat transfer between two walls separated by air, emphasizing the need to calculate heat flux for each mechanism separately.

PREREQUISITES
  • Understanding of thermal radiation principles, including Stefan-Boltzmann law
  • Knowledge of convective heat transfer coefficients
  • Familiarity with heat transfer equations and concepts
  • Basic thermodynamics, particularly temperature gradients
NEXT STEPS
  • Study the Stefan-Boltzmann law for radiation heat transfer calculations
  • Learn about convective heat transfer coefficients and their determination
  • Explore the impact of temperature gradients on heat transfer rates
  • Investigate the significance of conduction, convection, and radiation in thermal systems
USEFUL FOR

Engineers, physicists, and students in thermal dynamics or heat transfer, particularly those involved in designing thermal systems or analyzing heat transfer mechanisms in various environments.

zenite
Messages
12
Reaction score
0
Lets say a hot object is at 500K and placed in a chamber with wall temperature of 300K. The surrounding air in the chamber is 320K.

So what is the mode of heat transfer for the hot objection? There is convection and radiation. so the heat transfer rate, q = q(conv) + q(rad), right?

Convection is between object and surrounding air. But what about radiation? Is it between the object and the chamber walls or is it between the object and the surrounding air? Depending on which is chosen, the q(rad) will varies since q(rad) depends on the temperature difference of the 2 body.

Can anyone help me out? I am confused on using 500K and 300K to calculate q(rad) or 500K and 320K.
 
Science news on Phys.org
Ok, I think I got it. Please correct me if I am wrong.

Rate of energy radiation of an object (T is given by
qo = A\sigma\epsilonT4

If the object is in a chamber with wall temperature of Tw and surrounding air of Ta, then the object receives heat radiation from both wall and air.
qwall to object = A\sigma\epsilonTw4

qair to object = A\sigma\epsilonTa4

Hence, the net q for object to air and wall is:
qnet = A\sigma\epsilon(T4-Ta4-Tw4)

ps: the sigma and epsilon isn't suppose to be superscript, not sure why it turns out this way
 
Hi zenite, welcome to PF. The air isn't going to participate to any significant effect in the heat transfer between the object and the wall. (Another way of looking at this is that a few meters of air won't block radiative heat transfer, just as a few meters of air doesn't attenuate visible light to any noticeable degree). The air properties are only going to affect the convection term.
 
Ok, so radiation takes place between the object and the walls only? Is there no radiation taking place between the air and the object or is it insignificant as compared to the other modes of heat transfer?

And yes, I realized that the formula that I put up earlier on is incorrect, since taking T4 - Ta4 - Tw4 can give a negative value, which is illogical if T>Ta>Tw.
 
zenite said:
Ok, so radiation takes place between the object and the walls only? Is there no radiation taking place between the air and the object or is it insignificant as compared to the other modes of heat transfer?

It exists but is insignificant.
 
Oh thanks for clearing my doubts. I have another question on convection.

If an air gap exists between 2 walls, say, wall A and wall B. the convective heat transfer coefficient of the air is h. Assuming no radiation and conduction in the air gap, what is the heat transfer rate between the 2 walls?

Let Ta be temperature of wall A, Tb of wall B and Tair of the air.

q = hA (Ta - Tair) + hA (Tair - Tb) = hA (Ta - Tb)
or is it...
q = 0.5hA (Ta - Tb)

Since convection takes place 'twice', between wall A and air, and between wall B and air, should the h be multiply by 0.5?
 
Last edited:
I don't think this approach is going to prove fruitful. Convection removes heat energy by fluid motion tangential to a surface. The convective flow isn't going to automatically divert to the other wall and deposit heat energy there. And I don't see the sense in adding the heat flux values together. Assuming that convection does dominate in this problem (which isn't clear), it's the same flux of energy; adding the values is nonsensical.

The general approach is to calculate the values of heat flux by each mechanism (conduction, convection, radiation) and determine if one or more can be assumed negligible.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 14 ·
Replies
14
Views
3K
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 28 ·
Replies
28
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
5K