Radiation Problem: Find Surface Area of Light Bulb Filament

[brilapwnzall]

Homework Statement

The filament of a light bulb has a temperature of 3.2*10^3°C and radiates 59 watts of power. The emissivity of the filament is 0.38. Find the surface area of the filament.

Homework Equations

$$\Delta$$Q/$$\Delta$$T=e$$\sigma$$AT^4

$$\sigma$$=5.67*10^-8

The Attempt at a Solution

59=(.38)(5.67*10^-8)(A)(3.2*10^3)^4

Use needed Algebra to solve for A and I get 2.61e-5, but it's not the right answer.
Can someone please tell me what I am doing wrong?

 

[rock.freak667]

Your temperature 3.2*10^3°C is in Celsius, you need to convert it to Kelvin (K).

 

[gneill]

What temperature scale is implied by the Stefan-Boltzmann constant?