Radical and its rational exponential form

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SUMMARY

The discussion centers on the equivalence of the expressions sqrt((-3)^2) and (-3)^2/2, highlighting a common misconception in mathematical interpretation. Participants assert that while sqrt(9) equals 3, the expression (-3)^2/2 can be misleading, particularly in the context of complex numbers. The consensus is that these forms are not universally equivalent, especially when considering the properties of square roots and the need to select specific roots in complex analysis.

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  • Familiarity with complex numbers and their operations
  • Knowledge of exponentiation rules
  • Basic algebraic manipulation skills
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  • Study the properties of square roots in real and complex numbers
  • Learn about the implications of choosing roots in complex analysis
  • Explore the differences between real and complex exponentiation
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OceanSpring
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Can someone explain how these are equivalent.

sqrt((-3)^2) = (-3)^2/2

=sqrt(9) and (-3)^1

3 is not equal to -3

(-3)^2/2 can be expressed as:

(-3^2)^1/2 and (-3^1/2)2

(9)^1/2 and (sqrt(-1)sqrt(3))^2

3 is not equal to -3

Every textbook I've come across says these forms are equivalent. This seems totally inconsistent.
 
Last edited:
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sqrt((-3)^2) = (-3)^2/2
That is not true. This rule applies to positive numbers in the inner bracket only.

In the complex numbers, you have to choose which root you would like to take (as there are always two, apart from sqrt(0), so sqrt(9)=-3 is... well, not completely wrong, but not really right.
 

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