# De-Nesting Radicals: Solving & Simplifying Solutions

• bamajon1974
They are not solutions to the equation that is the square root of the nested radical. They are only solutions to the equation defined by assuming the simplified form.
bamajon1974
I want to de-nest the following radical:
(1) $$\sqrt{3+2\sqrt{2}}$$
Into the general simplified form:
(2) $$a+b\sqrt{2}$$
Equating (1) with (2),
(3) $$\sqrt{3+2\sqrt{2}} = a+b\sqrt{2}$$
and squaring both sides:
(4) $$3+2\sqrt{2} = a^2 + 2b^2 + 2ab\sqrt{2}$$
generates a system of two equations with two unknowns, a and b, after equating the rational and irrational parts:
(5) $$3 = a^2 + 2b^2$$
(6) $$2\sqrt{2} = 2ab\sqrt{2}$$
Simplifying (6) and solving for b:
(7) $$b=\frac{1}{a}$$
Substituting (7) into (5) yields:
(8) $$3 = a^2 + 2\frac{1}{a^2}$$
Clearing the denominator and moving non-zero terms to one side generates a quartic equation:
(9) $$0 = a^4 - 3a^2 +2$$
(10) $$x=a^2, x^2 = (a^2)^2 = a^4, x = \pm \sqrt{a}$$
(11) $$0 = x^2 - 3x + 2$$
The square root of the discriminant is an integer, 1, which presumably makes simplification of the nested radical possible. Finding the roots, x, of (11) gives
(12)$$x=1, x =\sqrt{2}$$
Substituting the roots in (12) into (10) gives a:
(13) $$a = \pm \sqrt{2} , a = \pm 1$$
Then b is found from (7):
(14) $$b = \pm \frac{1}{\sqrt{2}} , b = \pm 1$$
Using the positive values of a and b, the de-nested radical is:
(15) $$\sqrt{3+2\sqrt{2}} = 1+\sqrt{2}$$

My questions are:
(1) Is this approach for simplifying nested radical correct?

(2) The positive values of a and b produce the correct simplified form in (15) while the negative values of a and b do not. Is there a way to figure out which roots from (9) are correct and which to reject other than calculating the numerical value of (15) with both positive and negative a's and b's to see which is equal to the nested form?

(3) I have also seen the general simplified de-nested form as:
(16) $$\sqrt{a} + \sqrt{b}$$
Going through an analogous process as above, it generates the correct simplified form in (15) as well. Is one form (2) or (15) better than the other? Or is it just a personal preference which one to use?

Thanks!

The square root radical symbol means, the expression under the radical raised to the one-half power.

$$\sqrt{3+2\sqrt{2}}$$
$$(3+2\sqrt{2})^(1/2)$$
$$(3+2(2)^(1/2))^(1/2)$$

( I KNOW what I'm trying to do but still cannot make it appear correctly)

symbolipoint said:
The square root radical symbol means, the expression under the radical raised to the one-half power.

$$\sqrt{3+2\sqrt{2}}$$
$$(3+2\sqrt{2})^{(1/2)}$$
$$(3+2(2)^{(1/2}))^{(1/2)}$$

( I KNOW what I'm trying to do but still cannot make it appear correctly)

You mean like this? Just enclose your expression for the exponent in a pair of curly braces {}.

bamajon1974 said:
(12)$$x=1, x =\sqrt{2}$$

bamajon1974 said:
Substituting the roots in (12) into (10) gives a:
(13) $$a = \pm \sqrt{2} , a = \pm 1$$

I'll give you a chance to look at these again. You've ended up with the correct answer however because you made two errors that both canceled each other out, so that was a lucky one on your part ;)

bamajon1974 said:
My questions are:
(1) Is this approach for simplifying nested radical correct?
Yes.

bamajon1974 said:
(2) The positive values of a and b produce the correct simplified form in (15) while the negative values of a and b do not. Is there a way to figure out which roots from (9) are correct and which to reject other than calculating the numerical value of (15) with both positive and negative a's and b's to see which is equal to the nested form?
You'll often have situations arise whereby you need to find, say, the length of an object, but the equations you're dealing with are quadratics and will thus give you two solutions, a positive and a negative one. It suffices to toss away the negative value because you're solving a problem that only makes sense with a positive answer.

It's similar in this case. You're trying to simplify a square root. You know that square roots don't give negative results so you're allowed to simply toss out the result $-1-\sqrt{2}$ because that is clearly negative and can't be the answer. You don't need to look at the numerical values of each result with a calculator if you simply use a bit of intuition.

bamajon1974 said:
(3) I have also seen the general simplified de-nested form as:
(16) $$\sqrt{a} + \sqrt{b}$$
Going through an analogous process as above, it generates the correct simplified form in (15) as well. Is one form (2) or (15) better than the other? Or is it just a personal preference which one to use?

Thanks!
I prefer yours merely because the $\sqrt{2}$ result cancels and you end up with a nice result in (7). Neither are incorrect, but also both are assumptions. You assumed that the answer is of the form $a+b\sqrt{2}$ and the "general" simplified de-nested form $\sqrt{a}+\sqrt{b}$ assumes that the result is the sum of two square roots. What if it were $\sqrt{a}+\sqrt{b}+\sqrt{c}$ instead? Or something even more complicated?
So yes, I prefer your assumption over the other because yours is easier to work with.

I see my error:
12)
$$x=1, x=\sqrt{2}$$
Should be
$$x=1, x=2$$
My bad. Although in my defense that was an error I didn't catch after typing so much unfamiliar latex code into these lines.

I had neglected to mention that in the if you try to de-nest
$$\sqrt{3+2\sqrt{2}}$$
by assuming it equals the other simplified form (16)
$$\sqrt{a} + \sqrt{b}$$
Equating the nested radical with the assumed simplified form and squaring both sides:
$$3 + 2\sqrt{2} = a + b + 2\sqrt{ab}$$
Equating rational and irrational parts generates 2 equations with 2 unknowns:
$$3 = a + b$$
$$2\sqrt{2} = 2\sqrt{ab}$$
Solving for b in the second equation, substituting into the first and moving all non-zero terms to one side of the equation generates a quadratic:
$$0=a^2+3a+2$$
of which the roots, a, are
$$a= 1, a=2$$
So a and b are
$$a=1, b=2$$
or
$$a=2, b=1$$
So the simplified form is
$$1+\sqrt{2}$$
identical to above, but I didn't have any negative roots to discard. So in this particular case, the second form was a little easier.

I see why rejecting the negative roots is justified as well.

## Related to De-Nesting Radicals: Solving & Simplifying Solutions

Radicals are mathematical expressions that contain a root symbol (√) and a radicand, which is the number or variable under the root symbol. They are used to represent numbers that cannot be simplified into whole numbers or fractions.

## 2. How do you simplify radicals?

To simplify radicals, you need to find the largest perfect square that is a factor of the radicand. Then, you can write the radical as the product of the square root of the perfect square and the remaining number or variable. This process is known as "pulling out" the perfect square.

## 3. What is the process of de-nesting radicals?

De-nesting radicals involves simplifying radicals within radicals. This is done by first simplifying the innermost radical, and then carrying out the same process on the remaining radicals until there are no more nested radicals.

## 4. How do you solve equations with radicals?

To solve equations with radicals, you need to isolate the radical on one side of the equation and then square both sides to eliminate the radical. However, it is important to check the solutions obtained, as squaring both sides may introduce extraneous solutions.

## 5. Why is it important to simplify and de-nest radicals?

Simplifying and de-nesting radicals allows us to solve equations and perform operations with radicals more easily. It also helps in understanding the relationship between radicals and their corresponding whole number or fractional expressions, making it easier to work with them in various mathematical contexts.

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