Radioactive Dating with Potassium Argon

[Badger]

[SOLVED] Radioactive Dating with Potassium Argon

Homework Statement

The technique known as potassium-argon dating is used to date old lava flows. The potassium isotope ^{40}{\rm K} has a 1.28 billion year half-life and is naturally present at very low levels. ^{40}{\rm K} decays by beta emission into ^{40}{\rm Ar}. Argon is a gas, and there is no argon in flowing lava because the gas escapes. Once the lava solidifies, any argon produced in the decay of ^{40}{\rm K} is trapped inside and cannot escape. A geologist brings you a piece of solidified lava in which you find the ^{40}{\rm Ar}/^{40}{\rm K} ratio to be 0.350.

t = ? [billions of years]

Homework Equations

Any of these I suppose:
N = N_0 e^(-t/T)
T = time constant = 1/r
r = decay rate = [per seconds]
(t/2) = half-life = 1.28 billion years
Beta-plus decay: X becomes Y (A same, Z-1) + e^+1 + energy

The Attempt at a Solution

N = given ratio of Ar/K = .350
N_0 = 1

ln(1/2) = -(t/2) / T
T = -t/2 / ln(.5) = 1.846... years
r = 1 / T = 5.41 * 10^-10 [yr^-1]

.350 = 1e^(-rt)
t = ln .350 / -r = 1,938,653,661
t = 1.94 billion years

different attempt using
N = N_0 * (.5)^t/(t/2)
t/2 = given halflife, N = ratio = .350, N_0 = 1
t = 1.94 billion years

I'm guessing I shouldn't be putting in the ratio of Ar to K in for N. But my book only goes into details about Carbon-dating, so I'm not sure where to go from here.

Cheers.

 

[Kurdt]

Bit of a tricky question. What you can do however is say that:

N_{Ar}/N = 0.35 where N is the amount of potassium after decay, and,

N_0 = N_{Ar} + N

That should help you if you have some Carbon dating examples.

 

[Badger]

Thanks that worked out flawlessly.