- #31
Vuldoraq
- 265
- 1
Looks good to me. 
Radioactive Decay Differential Equation Question
- Thread starter TFM
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SUMMARY
The discussion focuses on solving a radioactive decay problem involving a fictional element, Unobtainium, with a decay rate described by the differential equation u' = -k u. The half-life of Unobtainium is established as 2.3 × 10^9 years, leading to the calculation of the decay constant k as k = ln(2) / (2.3 × 10^9). Furthermore, participants calculate the number of decay events per second for a 1 kg block of Unobtainium, which has an atomic mass of 415 g/mol, resulting in approximately 1.39 × 10^7 decay events per second.
PREREQUISITES- Understanding of differential equations, specifically exponential decay.
- Knowledge of half-life calculations in radioactive decay.
- Familiarity with Avogadro's number and molar mass concepts.
- Basic logarithmic functions and their properties.
- Explore the derivation of decay constants in radioactive materials.
- Learn about the application of differential equations in physical sciences.
- Study the relationship between half-life and decay rates in various isotopes.
- Investigate the significance of Avogadro's number in chemical calculations.
This discussion is beneficial for students and professionals in physics, chemistry, and engineering, particularly those involved in nuclear science and radioactive material handling.
- #32
TFM
- 1,016
- 0
Execellent.
Thanks for your assitance, Vuldoraq and Tiny-Tim
TFM
Thanks for your assitance, Vuldoraq and Tiny-Tim
TFM
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