Radius and centripetal relation

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SUSUSUSUSUSUSUSU

Homework Statement


the file given

Homework Equations



F=mv^2/r

The Attempt at a Solution


I do not understand why the centripetal force is 2a and not 2/a since the radius of X is twice longer.

When I use the equation above, raidius is inversely proportional to the acceleration.

Is radius proportional to the accerlation? Then why it is?[/B]


 
Attachments
  • Physics exam question 22: a circular horizontal disc with a curved arrow showing rotation, point X at distance 2L from the centre and point Y at distance L, with a table of answer options for linear speed and centripetal acceleration of X.
    스크린샷 2017-10-30 13.48.53.png
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Both speed and radius change. And I don't see how you would place the a in the denominator. That doesn't even give an acceleration in terms of units.
The angular velocity is constant. There is an expression for the acceleration that uses the angular velocity, that makes the problem easier.
 
so
mfb said:
Both speed and radius change. And I don't see how you would place the a in the denominator. That doesn't even give an acceleration in terms of units.
The angular velocity is constant. There is an expression for the acceleration that uses the angular velocity, that makes the problem easier.
sorry i got a/2 hahah
 
SUSUSUSUSUSUSUSU said:
so

sorry i got a/2 hahah

when i use 2R, the equation will be mv^2/2R which is a/2. this is what i have got